The energy required to charge a parallel plate condenser of plate separation $d$ and plate area of…

The energy required to charge a parallel plate condenser of plate separation $d$ and plate area of cross-section A such that the uniform electric field between the plates is E, is
  1. $\frac{1}{2} \varepsilon_0 E^2 A d$
  2. $\frac{1}{2} \varepsilon_0 E^2 / A . d$
  3. $\varepsilon_0 E^2 / A d$
  4. $\varepsilon_0 \mathrm{E}^2 A d$

Solution

$\text {Energy required }=\frac{1}{2} C V^2=\frac{1}{2} \varepsilon_0 E^2 \mathrm{Ad}$

Asked in: NEET 2008 (Mains)

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