The energy released per fission of nucleus of ${}^{240}X$ is $200 MeV$ . The energy released if all the atoms in $120 g$ of pure ${}^{240}X$ undergo fission is _____ $\times 10^{25} MeV$ .
(Given $N_{A} = 6 \times 10^{23}$ )

Question

The energy released per fission of nucleus of ${}^{240}X$ is $200 MeV$ . The energy released if all the atoms in $120 g$ of pure ${}^{240}X$ undergo fission is _____ $\times 10^{25} MeV$ .

(Given $N_{A} = 6 \times 10^{23}$ )

Aicharya · Accepted Answer

Energy released per fission is 200 &#160; MeV . The number of atoms n in 120 &#160; g : n = 120 240 &#215; 6 &#215; 10 23 &#160; atoms . Total energy released, E = n &#215; 200 &#215; 10 6 = 6 &#215; 10 25 &#160; MeV

The energy released per fission of nucleus of X 240 is 200   MeV . The energy released if all the atoms…

Solution

The energy released per fission of nucleus of X 240 is 200 &#160; MeV . The energy released if all the atoms…

Solution

The energy released per fission of nucleus of X 240 is 200 MeV . The energy released if all the atoms…