The energy of $E$ of a system is function of time $t$ and is given by $E(t)=\alpha t-\beta t^3$, where…

The energy of $E$ of a system is function of time $t$ and is given by $E(t)=\alpha t-\beta t^3$, where $\alpha$ and $\beta$ are constants. The dimensions of $\alpha$ and $\beta$ are
  1. $\left[\mathrm{ML}^2 T^{-1}\right]$ and $\left[\mathrm{ML}^2 T\right]$
  2. $\left[\mathrm{LT}^{-1}\right]$ and $[\mathrm{LT}]$
  3. $\left[\mathrm{ML}^2 \mathrm{~T}^{-3}\right]$ and $\left[\mathrm{ML}^2 \mathrm{~T}^{-5}\right]$
  4. $\left[\mathrm{MLT}^{-1}\right]$ and $[\mathrm{MLT}]$

Solution

Energy of the system as a function of time, $E(t)=\alpha t-\beta t^3$ Where, $\alpha$ and $\beta$ are constant. According to principle of homogenity, dimension of $\alpha t=$ dimension of energy i.e $\Rightarrow \quad[\alpha][t]=[E]$ $\begin{array}{rrr}\Rightarrow & {[\alpha][\mathrm{T}]=\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]} \\ \Rightarrow & {[\alpha]=\left[\mathrm{ML}^2 \mathrm{~T}^{-3}\right]}\end{array}$ Again, dimension of $\beta t^3=$ dimension of energy $\begin{array}{ll}\Rightarrow & {[\beta]\left[t^3\right]=\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]} \\ \Rightarrow & {[\beta]\left[\mathrm{T}^3\right]=\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]}\end{array}$ $\Rightarrow \quad[\beta]=\left[\mathrm{ML}^2 \mathrm{~T}^{-5}\right]$

Asked in: AP EAMCET 2022 (05 Jul Shift 1)

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