The energy of an electromagnetic radiation is $19.875 \times 10^{-13}$ ergs. What is its wave number in…

The energy of an electromagnetic radiation is $19.875 \times 10^{-13}$ ergs. What is its wave number in $\mathrm{cm}^{-1}$ ? $\left(h=6.625 \times 10^{-27}ight.$ erg sec, $\left.c=3 \times 10^{10} \mathrm{~cm} \mathrm{sec}^{-1}ight)$
  1. $1000$
  2. $10^6$
  3. $100$
  4. $10000$

Solution

$\begin{aligned} & E=h v=h \times \frac{c}{\lambda}=h \times c \cdot \bar{v} \\ & \therefore \quad \bar{v}=\frac{E}{h c}=\frac{19.875 \times 10^{-13}}{6.625 \times 10^{-27} \times 3 \times 10^{10}}=10^4\end{aligned}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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