The energy of a photon in a monochromatic light of wavelength $621 \mathrm{~nm}$ matches with the band gap…

The energy of a photon in a monochromatic light of wavelength $621 \mathrm{~nm}$ matches with the band gap of a semiconducting material. Then the minimum energy required to create an electron-hole pair from the semiconductor is [Take hc $=1242 \mathrm{eV}-\mathrm{nm}$, where h is Planck's constant and $\mathrm{c}$ is speed of light in vacuum]
  1. $3.4 \mathrm{eV}$
  2. $1.7 \mathrm{eV}$
  3. $2 \mathrm{eV}$
  4. $2.2 \mathrm{eV}$

Solution

Minimum energy required $=\frac{1242}{621} \mathrm{eV}=2 \mathrm{eV}$

Asked in: AP EAMCET 2022 (06 Jul Shift 1)

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