The energy (in eV) possessed by a neon atom at $77^{\circ} \mathrm{C}$ is (Blotzmann constant,…

The energy (in eV) possessed by a neon atom at $77^{\circ} \mathrm{C}$ is (Blotzmann constant, $\mathrm{K}_{\mathrm{B}}=1.38 \times 10^{-23} \mathrm{~J} \mathrm{~K}^{-1}$ )
  1. $1.32 \times 10^{-3}$
  2. $3.20 \times 10^{-4}$
  3. $4.52 \times 10^{-2}$
  4. $3.88 \times 10^{-2}$

Solution

Temperature, $\mathrm{T}=77^{\circ} \mathrm{C}=273+77=350 \mathrm{~K}$ Boltzman constant, $\mathrm{K}_{\mathrm{B}}=1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K}$ Energy is given by, $\mathrm{E}=\frac{3}{2} \mathrm{~K}_{\mathrm{B}} \mathrm{T}$ $ \begin{aligned} & E=\frac{3}{2} \times 1.38 \times 10^{-23} \times 350 \\ & E(e V)=\frac{1.5 \times 1.38 \times 350 \times 10^{-23}}{1.6 \times 10^{-19}} \\ & E(e V)=4.52 \times 10^{-2} \mathrm{eV} \end{aligned} $

Asked in: AP EAMCET 2023 (18 May Shift 2)

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