The energy dissipated by a resistor is 10   mJ in 1   s , when an electric current of 2   mA…

The energy dissipated by a resistor is 10 mJ in 1 s, when an electric current of 2 mA flows through it. The resistance is ________Ω. (Round off to the Nearest Integer)

Solution

Q=i2RT

R=Qi2t=10×10-34×10-6×1=2500 Ω

Asked in: JEE Main 2021 (16 Mar Shift 2)

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