The energies of activation for forward and reverse reactions for $\mathrm{A}_{2}+\mathrm{B}_{2}…

The energies of activation for forward and reverse reactions for $\mathrm{A}_{2}+\mathrm{B}_{2} ightleftharpoons 2 \mathrm{AB}$ are $180 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and $200 \mathrm{~kJ} \mathrm{~mol}^{-1}$ respectively. The presence of a catalyst lowers the activation energy of both (forward and reverse) reactions by $100 \mathrm{k}$. $\mathrm{mol}^{-1} .$ The enthalpy change of the reaction $\left(\mathrm{A}_{2}+\mathrm{B}_{2} ightarrowight.$ $2 \mathrm{AB}$ ) in the presence of a catalyst will be (in $\mathrm{kJ} \mathrm{mol}^{-1}$ ) ______
  1. -20
  2. -15
  3. 20
  4. 15

Solution

Presence of catalyst does not affect enthalpy change
of reaction $\Delta \mathrm{H}_{\mathrm{R}}=\mathrm{E}_{\mathrm{f}}-\mathrm{E}_{\mathrm{b}}=180-200=-20 \mathrm{~kJ} / \mathrm{mol}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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