The energies $E_1$ and $E_2$ of two radiations are $25 \mathrm{eV}$ and $50 \mathrm{eV}$ respectively. The…
The energies $E_1$ and $E_2$ of two radiations are $25 \mathrm{eV}$ and $50 \mathrm{eV}$ respectively. The relation between their wavelengths i.e., $\lambda_1$ and $\lambda_2$ will be
$\lambda_1=2 \lambda_2$
$\lambda_1=4 \lambda_2$
$\lambda_1=\frac{1}{2} \lambda_2$
$\lambda_1=\lambda_2$
Solution
$\begin{aligned}
& E_1=25 \mathrm{eV}, E_2=50 \mathrm{eV} \\
& E_1=\frac{h c}{\lambda_1} \text { and } E_2=\frac{h c}{\lambda_2} \\
& \text { or } \frac{E_1}{E_2}=\frac{\lambda_2}{\lambda_1}
\end{aligned}$
or $\frac{25}{50}=\frac{\lambda_2}{\lambda_1}$
or $\lambda_1=2 \lambda_2$