The end product $\mathrm{C}$ of the following reaction is $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2} \stackrel{\mathrm{HNO}_{2}}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{PCl}_{5}}{\longrightarrow} \mathrm{B} \frac{\mathrm{NH}_{3}}{ ext { alcohol }} \longrightarrow \mathrm{C}$

Question

The end product $\mathrm{C}$ of the following reaction is $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2} \stackrel{\mathrm{HNO}_{2}}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{PCl}_{5}}{\longrightarrow} \mathrm{B} \frac{\mathrm{NH}_{3}}{	ext { alcohol }} \longrightarrow \mathrm{C}$

The end product $\mathrm{C}$ of the following reaction is $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}…