The emf of cell Tl $\left|\underset{(0.001 \mathrm{M})}{\mathrm{Tl}^{+}}\right|\left|\underset{(0.01…

The emf of cell Tl $\left|\underset{(0.001 \mathrm{M})}{\mathrm{Tl}^{+}}\right|\left|\underset{(0.01 \mathrm{M})}{\mathrm{Cu}^{2+}}\right| \mathrm{Cu}$ is $0.83 \mathrm{~V}$ at $298 \mathrm{~K}$. It could be increased by :
  1. decreasing concentration of both \(\mathrm{Tl}^{+}\) and \(\mathrm{Cu}^{2+}\) ions
  2. increasing concentration of \(\mathrm{Cu}^{2+}\) ions
  3. increasing concentration of \(\mathrm{T1}^{+}\)ions
  4. increasing concentration of both \(\mathrm{Tl}^{+}\) and \(\mathrm{Cu}^{2+}\) ions

Solution

$\begin{array}{ll} \text{Anodic Reaction} & {\left[\mathrm{T} \ell_{(s)} \rightarrow \mathrm{T}^{+}{ }_{(\mathrm{aq})}+\mathrm{e}^{-}\right] 2} \\ \text{Cathodic Reaction} & \mathrm{Cu}^{+2}{ }_{(\mathrm{aq})}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}_{(\mathrm{s})} \\ \hline \text{Overall Redox Reaction} & 2 \mathrm{~T} \ell_{(\mathrm{s})}+\mathrm{Cu}^{+2}{ }_{(\mathrm{aq})} \rightarrow 2 \mathrm{~T} \ell_{(\mathrm{aq})}^{+}+\mathrm{Cu}_{(\mathrm{s})} \end{array}$ $\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^o-\frac{0.0591}{2} \log \frac{\left[\mathrm{T} \ell^{+}\right]^2}{\left[\mathrm{Cu}^{+2}\right]}$ $\mathrm{E}_{\text {cell }}$ increases by increasing concentration of $\left[\mathrm{Cu}^{+2}\right]$ ions.

Asked in: JEE Main 2024 (08 Apr Shift 2)

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