The elevation of boiling point of 0 . 10 m aqueous CrCl 3 . xNH 3 solution is two times that of 0 . 05 &#160…

The elevation of boiling point of 0.10m aqueous CrCl3.xNH3 solution is two times that of 0.05 m aqueous CaCl2 solution. The value of x is ..
[Assume 100% ionisation of the complex and CaCl2, coordination number of Cr as 6, and that all NH3 molecules are present inside the coordination sphere]

Solution

0.05m aqueous CaCl2 =0.15molal solution of non electrolyte

Since the elevation in boiling point is double so the molality of given solution of complex =0.3m

Hence the complex must be producing three ions in the solution, so its formula =CrNH35ClCl2

SO X=5

Asked in: JEE Main 2020 (06 Sep Shift 1)

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