The elevation in boiling point of a solution of $10 \mathrm{~g}$ of a binary electrolyte (of molecular mass…

The elevation in boiling point of a solution of $10 \mathrm{~g}$ of a binary electrolyte (of molecular mass 100) in $100 \mathrm{~g}$ of water is $\Delta T_b$. Then, the value of $K_b$ for water is
  1. $\frac{\Delta T_b}{2}$
  2. 10
  3. $10 \Delta T_b$
  4. $\frac{\Delta T_b}{10}$

Solution

Weight of solute $=10 \mathrm{~g}$ Weight of solvent $=100 \mathrm{~g}$ Molecular mass of electrolyte $=100$ $ \begin{aligned} \Delta T_b & =i \times K_b \times \frac{\text { wt. of solute }}{\text { molecular mass }} \times \frac{1000}{\text { wt. of solvent }} \\ & =2 \times K_b \times \frac{10}{100} \times \frac{1000}{100} \end{aligned} $ $ \begin{aligned} \Delta T_b & =2 \times K_b \\ K_b & =\frac{\Delta T_b}{2} \end{aligned} $

Asked in: AP EAMCET 2021 (24 Aug Shift 1)

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