The element with Z = 120 (not yet discovered) will be a/an

$\left[{\mathrm{Og}}_{118}\right]8{\mathrm{s}}^2$ is the configuration for $\mathrm{Z}=120$.

Since the differentiating electron is entering in the $\mathrm{s}-$orbital, the element will belong to the s-block and the outermost s-orbital is having two electrons. Hence, It will belong to the alkaline earth metal group.