The element $X$ on reaction with conc. $\mathrm{HNO}_3$ forms two acidic oxides $A$ and $B$ of different…
The element $X$ on reaction with conc. $\mathrm{HNO}_3$ forms two acidic oxides $A$ and $B$ of different shapes. Element $Z$ on reaction with conc. $\mathrm{H}_2 \mathrm{SO}_4$ forms two acidic oxides $A$ and $D$ of different shapes. What are $X$ and $Z$ ?
C, C
S, Cu
C, S
C, Cu
Solution
$
\begin{aligned}
& \mathrm{C}+4 \mathrm{HNO}_3 \longrightarrow \mathrm{CO}_2+4 \mathrm{NO}_2+2 \mathrm{H}_2 \mathrm{O} \\
& \mathrm{C}+2 \mathrm{H}_2 \mathrm{SO}_4 \longrightarrow \mathrm{CO}_2+2 \mathrm{SO}_2+2 \mathrm{H}_2 \mathrm{O}
\end{aligned}
$
$\mathrm{CO}_2$ and $\mathrm{SO}_2$ both are acidic