The electrons identified by quantum numbers \(\mathrm{n}\) and \(\mathrm{I}\) : a) \(n=4,l=1\) b) \(n=4,…

The electrons identified by quantum numbers \(\mathrm{n}\) and \(\mathrm{I}\) : a) \(n=4,l=1\) b) \(n=4, l=0\) c) \(n=3,l=2\) d) \(n=3, l=1\) Can be placed in order of increasing energy
  1. (a) \( < \) (c) \( < \) (b) \( < \) (d)
  2. (c) \( < \) (d) \( < \) (b) \( < \) (a)
  3. (d) \( < \) (b) \( < \) (c) \( < \) (a)
  4. (b) \( < \) (d) \( < \) (a) \( < \) (c)

Solution

The greater is the value of \((n+1)\), the greater is the energy of orbitals.
(a) \(n=4, l=1 \Rightarrow 4 p\) orbital
(b) \(n=4, l=0 \Rightarrow 4\) s orbital
(c) \(n=3,l=2 \Rightarrow 3 d\) orbital
(d) \(n=3, l=1 \Rightarrow 3 p\) orbital
According to the Aufbau principle, energies of above-mentioned orbitals are in the order of-
The increasing order of energy (d) \(3 \mathrm{p} < \) (b) \(4 \mathrm{~s} < \) (c) \(3 \mathrm{~d} < \) (a) \(4 \mathrm{p}\)
So, (d) \( < \) (b) \( < \) (c) \( < \) (a) is correct order.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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