The electronic contigurations of four elements are given below. Arrange these elements in the correct order…

The electronic contigurations of four elements are given below. Arrange these elements in the correct order of magnitude of their electron affinity
(i) $2 \mathrm{~s}^{2} 2 \mathrm{p}^{5}$
(ii) $3 \mathrm{~s}^{2} 3 \mathrm{p}^{5}$
(iii) $2 \mathrm{~s}^{2} 2 \mathrm{p}^{4}$
(iv) $3 \mathrm{~s}^{2} 3 \mathrm{p}^{4}$
Select the correct answer using the codes
  1. (i) $ < (\mathrm{ii}) < (\mathrm{iii}) < (\mathrm{iv})$
  2. (ii) $ < (\mathrm{i}) < (\mathrm{iv}) < (\mathrm{iii})$
  3. (iii) $ < $ (iv) $ < (\mathrm{i}) < (\mathrm{ii})$
  4. (iii) $ < $ (iv) $ < (\mathrm{ii}) < (\mathrm{i})$

Solution

i. \(2 s^2 2 p^5 ightarrow 2 s^2 2 p^6\) Addition of an electron leads to a stable configuration. So the electron affinity will be high. ii. \(3 s^2 3 p^5 ightarrow 3 s^2 3 p^6\) Electron affinity is higher than (i) because the electron repulsions would be higher in (i) (owing to its small size). iii. \(2 s^2 2 p^4 ightarrow 2 s^2 2 p^5\) Lesser energy will be released than (i) and (ii) because of its electronic configuration (The configuration is not as stable as i). iv. \(3 s^2 3 p^4 ightarrow 3 s^2 3 p^5\) It releases more energy than (iii) and less energy than (ii) (The configuration is not as stable as ii). ^

Asked in: JEE-TOPICTESTS-CHEMISTRY

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