The electronic configuration which is associated with highest first ionisation enthalpy is:
- $[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^2$
- $[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^3$
- $[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^4$
- $[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^1$
Solution
Asked in: JEE-TOPICTESTS-CHEMISTRY
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