The electronic configuration of four elements $\mathrm{L}, \mathrm{P}, \mathrm{Q}$ and $\mathrm{R}$ are…
$\mathrm{L}\left(1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2} 2 \mathrm{p}^{4}ight) ; \mathrm{Q}\left(\mathrm{ls}^{2}, 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{2} 3 \mathrm{p}^{5}ight)$
$\mathrm{P}\left(\mathrm{ls}^{2}, 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{1}ight) ; \mathrm{R}\left(\mathrm{ls}^{2}, 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{2}ight)$
The formulae of ionic compounds that can be formed between these elements are
- $L_{2} P, R L, P Q$ and $R_{2} Q$
- $L P, R L, P Q$ and $R Q$
- $P_{2} L, R L, P Q$ and $R Q_{2}$
- $L P, R_{2} L, P_{2} Q$ and $R Q$
Solution
Asked in: JEE-TOPICTESTS-CHEMISTRY
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