The electronic configuration of \(\mathrm{Cs}\) is

The electronic configuration of \(\mathrm{Cs}\) is
  1. \([\mathrm{Kr}] 5 \mathrm{~s}^1\)
  2. \([\mathrm{Xe}] 6 \mathrm{~s}^1\)
  3. \([\mathrm{Rn}] 7 \mathrm{~s}^1\)
  4. \([\mathrm{Ar}] 4 \mathrm{~s}^1\)

Solution

Caesium atomic number is 55. Thus, electron configuration of caesium is \(1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 4 s^2 3 d^{10} 4 p^6 5 s^2 4 d^{10} 5 p^6 6 s^1\) or [Xe] \(6 s^1\). Hence, correct option is (b).

Asked in: AP EAMCET 2020 (21 Sep Shift 2)

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