The electronic configuration of an element is \(1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}, 3…
The electronic configuration of an element is \(1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{2}, 3 \mathrm{p}^{3}\). Which is the atomic number of the element which is just below the above element in the periodic table?
34
49
33
31
Solution
The atomic number of the above element is \(2+2+6+2+3=15\). The atomic number of the element below the given element is \(15+18=33\).
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