The electron of a hydrogen atom makes a transition from the $(n+1)^{\text {th }}$ orbit to the $n^{\text {th…
The electron of a hydrogen atom makes a transition from the $(n+1)^{\text {th }}$ orbit to the $n^{\text {th }}$ orbit. For large $\mathrm{n}$ the wavelength of the emitted radiation is proportional to
$n$
$n^3$
$n^4$
$n^2$
Solution
If $n_1=n$ and $n_2=n+1$ Maximum wavelength $\lambda_{\max }=\frac{n^2\left(n+1^2\right)}{(2 n+1 R)}$
Therefore, for large $\mathrm{n}, \lambda_{\max } \propto n^3$