The electron in hydrogen atom is initially in the third excited state. When it finally moves to ground state, the maximum number of spectral lines emitted are

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Aicharya · Accepted Answer

Initially the electron is in the third excited state i.e., $\mathrm{n}=4$ Hence maximum number of spectral lines emitted $=\frac{\mathrm{n}(\mathrm{n}-1)}{2}=\frac{4(4-1)}{2}=6$

The electron in hydrogen atom is initially in the third excited state. When it finally moves to ground state…

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