The electron in a hydrogen atom first jumps from the third excited state to the second excited state and…

The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths λ1λ2 of the photons emitted in this process is:
  1. 75
  2. 207
  3. 97
  4. 275

Solution

1λ1=R132-142= R×7144
1λ2=R122-132= R×536
⇒λ1λ2=R×536×144R×7=207

Asked in: JEE Main 2019 (12 Apr Shift 2)

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