The electrochemical equivalent of a metal is $3.3 \times 10^{-7} \mathrm{~kg}$ per coulomb. The mass of the…

The electrochemical equivalent of a metal is $3.3 \times 10^{-7} \mathrm{~kg}$ per coulomb. The mass of the metal liberated at the cathode when a 3 A current is passed for 2 seconds will be
  1. $19.8 \times 10^{-7} \mathrm{~kg}$
  2. $9.9 \times 10^{-7} \mathrm{~kg}$
  3. $6.6 \times 10^{-7} \mathrm{~kg}$
  4. $1.1 \times 10^{-7} \mathrm{~kg}$

Solution

$\mathrm{m}=$ Zit, $\mathrm{m}=3.3 \times 10^{-7} \times 3 \times 2=19.8 \times 10^{-7} \mathrm{~kg}$.

Asked in: JEE Main 2004

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