The electric intensity due to a dipole of length $10 \mathrm{~cm}$ and having a charge of $500 \mu \mathrm{C}$, at a point on the axis at a distance $20 \mathrm{~cm}$ from one of the charges in air, is

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Aicharya · Accepted Answer

We know, $\mathrm{E}=9 \times 10^9 \cdot \frac{2 \mathrm{pr}}{\left(\mathrm{r}^2-1^2\right)^2}$ where $\mathrm{p}=\left(500 \times 10^{-6}\right) \times\left(10 \times 10^{-2}\right)=5 \times 10^{-5} \mathrm{Cm}$ $\begin{aligned} \mathrm{r} & =25 \mathrm{~cm}=0.25 \mathrm{~m}, 1=5 \mathrm{~cm}=0.05 \mathrm{~m} \ \mathrm{E} & =\frac{9 \times 10^9 \times 2 \times 5 \times 10^{-5} \times 0.25}{\left\{(0.25)^2-(0.05)^2\right\}^2} \ & =6.25 \times 10^7 \mathrm{~N} / \mathrm{C} \end{aligned}$

The electric intensity due to a dipole of length $10 \mathrm{~cm}$ and having a charge of $500 \mu…

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