The electric flux over a sphere of radius ' $r$ ' is ' $\phi$ '. If the radius of the sphere is doubled…
The electric flux over a sphere of radius ' $r$ ' is ' $\phi$ '. If the radius of the sphere is doubled without changing the charge, the flux will be
- $4 \phi$
- $2 \phi$
- $\phi$
- $\frac{\phi}{2}$
Solution
Using Gauss's law, $\phi=\frac{q}{\varepsilon_0}$
$\begin{aligned}
& \quad \Rightarrow \phi \propto q \\
& \therefore \quad \frac{\phi_2}{\phi}=\frac{q}{q} \\
& \therefore \quad \\
& \therefore \quad
\end{aligned}$
..(charge q is kept the same)
*
Asked in: MHT CET 2024 (09 May Shift 2)
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