The electric flux is $\phi=\alpha \sigma+\beta \lambda$ where $\lambda$ and $\sigma$ are linear and surface…

The electric flux is $\phi=\alpha \sigma+\beta \lambda$ where $\lambda$ and $\sigma$ are linear and surface charge density, respectively. $\left(\frac{\alpha}{\beta}\right)$ represents
  1. electric field
  2. area
  3. charge
  4. displacement

Solution

$\begin{aligned} & \alpha \equiv \frac{\phi}{\sigma} \\ & \beta=\frac{\phi}{\lambda} \\ & \frac{\alpha}{\beta} \equiv \frac{\lambda}{\sigma} \equiv \text { displacement }\end{aligned}$

Asked in: JEE Main 2025 (23 Jan Shift 1)

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