The electric field intensity (E) at a distance of 3 m from a uniform long straight wire of linear charge…
The electric field intensity (E) at a distance of 3 m from a uniform long straight wire of linear charge density 0.2 m $\mathrm{Cm}^{-1}$ is
$1.2 \times 10^3 \mathrm{Vm}^{-1}$
$0.6 \times 10^3 \mathrm{Vm}^{-1}$
$1.8 \times 10^3 \mathrm{Vm}^{-1}$
$2.4 \times 10^3 \mathrm{Vm}^{-1}$
Solution
The electric field at a distance r from a uniform straight wire is
$\begin{aligned}
& \mathrm{E}=\frac{2 \mathrm{k} \lambda}{\mathrm{r}}=\frac{2 \times 9 \times 10^9 \times 0.2 \times 10^{-6}}{3} \\
& =1.2 \times 10^3 \mathrm{Vm}^{-1}
\end{aligned}$