The electric field ( $\overrightarrow{\mathrm{E}}$ in $\mathrm{NC}^{-1}$ ) in a region is given by…
The electric field ( $\overrightarrow{\mathrm{E}}$ in $\mathrm{NC}^{-1}$ ) in a region is given by $\overrightarrow{\mathrm{E}}=3 \hat{\mathrm{i}}+5 \tilde{\mathrm{i}}$. The net electric flux through a square area of side $2 \mathrm{~m}$ parallel to $\mathrm{y}-\mathrm{z}$ plane is
$3 \mathrm{NC}^{-1} \mathrm{~m}^2$
$6 \mathrm{NC}^{-1} \mathrm{~m}^2$
$12 \mathrm{NC}^{-1} \mathrm{~m}^2$
$24 \mathrm{NC}^{-1} \mathrm{~m}^2$
Solution
The net electric flux through a square area $A=2 \times 2=4 \mathrm{~m}^2$ parallel to $y-z$ plane only, as or.ly $\mathrm{i}$ component will cause any flux
$\therefore$ Flux $\phi=\overrightarrow{\mathrm{E}} \cdot \mathrm{A}=3 \times 4=12 \mathrm{~N} \mathrm{C}^{-1} \mathrm{~m}^2$.