The electric field in a region of space is given as $\mathbf{E}=\left(5 \mathrm{NC}^{-1}\right) x \hat{i}$.…

The electric field in a region of space is given as $\mathbf{E}=\left(5 \mathrm{NC}^{-1}\right) x \hat{i}$. Consider point $A$ on the $Y$-axis at $y=5 \mathrm{~m}$ and point $B$ on the $X$-axis at $x=2 \mathrm{~m}$. If the potentials at points $A$ and $B$ are $V_A$ and $V_B$ respectively, then $\left(V_B-V_A\right)$ is
  1. $-15 \mathrm{~V}$
  2. $8 \mathrm{~V}$
  3. $-10 \mathrm{~V}$
  4. $-12.5 \mathrm{~V}$

Solution

The given situation is shown below
Since, electric field is directed along the $X$ - axis, hence, point $A$ and $C$ lie on equipotential surface $\therefore$ Potential at point $C=$ Potential at point $A$ $\Rightarrow \quad V_C=V_A$ $\therefore \quad V_B-V_A=V_B-V_C$ $=-E \Delta x=-5(2-0)=-10 \mathrm{~V}$

Asked in: AP EAMCET 2022 (05 Jul Shift 1)

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