The electric field in a region of space is given as $\mathbf{E}=\left(5 \mathrm{NC}^{-1}\right) x \hat{i}$.…
- $-15 \mathrm{~V}$
- $8 \mathrm{~V}$
- $-10 \mathrm{~V}$
- $-12.5 \mathrm{~V}$
Solution

Since, electric field is directed along the $X$ - axis, hence, point $A$ and $C$ lie on equipotential surface $\therefore$ Potential at point $C=$ Potential at point $A$ $\Rightarrow \quad V_C=V_A$ $\therefore \quad V_B-V_A=V_B-V_C$ $=-E \Delta x=-5(2-0)=-10 \mathrm{~V}$
Asked in: AP EAMCET 2022 (05 Jul Shift 1)