The electric field in a region is given by E → = 2 5 E 0 i ^ + 3 5 E 0 j ^ with E 0 = 4 . 0 × 10…

The electric field in a region is given by E=25E0i^+35E0j^ with E0=4.0×103 N C-1. The flux of this field through a rectangular surface, area 0.4 m2 parallel to the Y-Z plane is _______ N m2 C-1.

Solution

ϕ=ExA25×4×103×0.4=640 N m2 C-1

Asked in: JEE Main 2021 (17 Mar Shift 2)

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