The electric field in a certain region is acting radially outward and is given by E = A r . A charge…

1. $4\mathrm{\pi }{\mathrm{ϵ}}_0\mathrm{A}{\mathrm{a}}^2$
2. $\mathrm{A}{\mathrm{ϵ}}_0{\mathrm{a}}^2$
3. $4\mathrm{\pi }{\mathrm{ϵ}}_0\mathrm{A}{\mathrm{a}}^3$
4. ${\mathrm{ϵ}}_0\mathrm{A}{\mathrm{a}}^3$

Solution

We know
${\mathrm{E}}_{\mathrm{Sphere}}=\frac{1}{4{\mathrm{\pi \epsilon }}_0}\frac{\mathrm{q}}{{\mathrm{r}}^2}\mathrm{ }$
$\frac{1}{4{\mathrm{\pi \epsilon }}_0}\frac{\mathrm{q}}{{\mathrm{a}}^2}=\mathrm{Aa}$
$\mathrm{q}=4{\mathrm{\pi \epsilon }}_0{\mathrm{Aa}}^3$

Asked in: NEET 2015 (Phase 1)

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