The electric field due to a short electric dipole at a distance $r$ on the axial line from its mid-point is…

The electric field due to a short electric dipole at a distance $r$ on the axial line from its mid-point is $x$ times the electric field at a distance $2 r$ on the equatorial line from the mid-point of dipole. Then, the value of $x$ is
  1. 16
  2. 9
  3. 25
  4. 36

Solution


On axis, field magnitude, $E_1=\frac{2 k p}{r^3}$ On equatorial axis, field magnitude $ E_2=\frac{k p}{(2 r)^3}=\frac{k p}{8 r^3} $ So, $ E_1=16 E_2 \Rightarrow x=16 $

Asked in: AP EAMCET 2018 (22 Apr Shift 2)

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