The electric field at point $\mathrm{p}$ due to an electric dipole is $\mathrm{E}$. The electric field at point $\mathrm{R}$ on equitorial line will be $\frac{\mathrm{E}}{x}$. The value of $x$ :

Question

Aicharya · Accepted Answer

$\begin{aligned} & E_P=\frac{2 K P}{r^3}=E \ & E_R=\frac{K P}{(2 r)^3}=\frac{E}{16} \ & x=16\end{aligned}$

The electric field at point $\mathrm{p}$ due to an electric dipole is $\mathrm{E}$. The electric field at…

Solution