The efficiency of Carnot heat engine

The efficiency of Carnot heat engine
  1. is independent of the temperature of the source and the sink
  2. is independent of the working substance
  3. can be $100 \%$
  4. is not affected by the thermal capacity of the source or the sink

Solution

We know that, the efficiency of Carnot heat engine is $ \eta=1-\frac{T_2}{T_1} $ where, $T_1=$ temperature of source (hot reservoir) $T_2=$ temperature of sink (cold reservoir) Hence, efficiency depends only on the temperature of hot and cold reservoir but independent of the working substance

Asked in: AP EAMCET 2021 (24 Aug Shift 1)

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