The d.r. of normal to the plane through $(1,0,0),(0,1,0)$ which makes an angle $\pi / 4$ with plane $x+y=3$…
- $1, \sqrt{2}, 1$
- $1,1, \sqrt{2}$
- $1,1,2$
- $\sqrt{2}, 1,1$
Asked in: JEE Main 2002
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