The domain of \(f(x)=\cos ^{-1}\left(\frac{x-3}{2}\right)-\log _{10}(4-x)\) is

The domain of \(f(x)=\cos ^{-1}\left(\frac{x-3}{2}\right)-\log _{10}(4-x)\) is
  1. \((1,4)\)
  2. $[1,4)$
  3. $[1,4)$
  4. \([1,4]\)

Solution

Let \(f(x)=\cos ^{-1}\left(\frac{x-3}{2}\right)-\log _{10}(4-x)\) For domain of \(\log _{10}(4-x) \Rightarrow 4-x > 0 \Rightarrow x < 4\) For domain of \(\cos ^{-1}\left(\frac{x-3}{2}\right) \Rightarrow-1 \leq \frac{x-3}{2} \leq 1\) \(\Rightarrow \quad 1 \leq x \leq 5\) Now domain of $f(x)$ will be $x \in [1,4)$

Asked in: AP EAMCET 2020 (17 Sep Shift 1)

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