Then $P[X=4]+P[X=5]=$The distribution function $\mathrm{F}(\mathrm{X})$ of discrete random variable $\mathrm{X}$ is given by Then…
Then $P[X=4]+P[X=5]=$- 0.14
- 0.85
- 0.37
- 0.23
Solution
$\begin{aligned}
& \therefore P(x=1)=0.2, P(x=2)=0.17, P(x=3)=0.11 \\
& P(x=4)=0.14, P 9 x=5)=0.23, P(x=6)=0.15
\end{aligned}$
Thus $\mathrm{P}(\mathrm{x}=4)+\mathrm{P}(\mathrm{x}=5)=0.14+0.23=0.37$Asked in: MHT CET 2021 (22 Sep Shift 2)