The distance time graph of a particle at time makes angles $45^{\circ}$ with the time axis. After one second…
The distance time graph of a particle at time makes angles $45^{\circ}$ with the time axis. After one second, it makes angle $60^{\circ}$ with the time axis. What is the acceleration of the particle?
$\sqrt{3}-1$
$\sqrt{3}+1$
$\sqrt{3}$
1
Solution
Velocity at time t is $\tan 45^{\circ}=1$. Velocity at time $(t=1)$ is $\tan 60^{\circ}=\sqrt{3}$. Acceleration is
change in velocity in one second $=\sqrt{3}-1$.
.
Asked in: JEE Mains - Motion In One Dimension - Test 2