The distance covered by a stone dropped from the top of a building in the last second of its motion is 0.36…

The distance covered by a stone dropped from the top of a building in the last second of its motion is 0.36 times the total distance travelled by it. The height of the building is (acceleration due to gravity $=9.8 \mathrm{~ms}^{-2}$ )
  1. 98.6 m
  2. 78.4 m
  3. 122.5 m
  4. 245 m

Solution

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Asked in: AP EAMCET 2017 (26 Apr Shift 2)

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