The distance between the successive node and anti-node is

1. \(\lambda\)
2. \(\frac{\lambda}{2}\)
3. \(\frac{\lambda}{4}\)
4. \(\frac{3 \lambda}{4}\)

Solution

The distance between the successive node and anti-node is equal to \(\frac{\lambda}{4}\), where \(\lambda\) is wavelength.

Asked in: MHT CET Full Test 10

Practice more Waves and Sound questions on Aicharya