The distance between the parallel lines $9 x^2-6 x y+y^2+18 x-6 y+8=0$ is

The distance between the parallel lines $9 x^2-6 x y+y^2+18 x-6 y+8=0$ is
  1. $\sqrt{10}$
  2. 2
  3. $\frac{2 \sqrt{153}}{\sqrt{10}}$
  4. $\frac{2}{\sqrt{10}}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2020 (07 Oct Special)

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