The dissolution of A l O H 3 by a solution of N a O H results in the formation of:

The dissolution of A l O H 3 by a solution of N a O H results in the formation of:
  1. A l H 2 O 4 O H 2 +
  2. A l H 2 O 3 O H 3
  3. A l   H 2 O 2 O H 4 –
  4. A l H 2 O 6 O H 3

Solution

(1) $\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}ight)_{4}(\mathrm{OH})_{2}ight]^{+}$
(2) $\mathrm{Al}(\mathrm{OH})_{3}$ dissolves in $\mathrm{NaOH}$ solution to give $\mathrm{Al}(\mathrm{OH})^{-4}$ ion which is supposed to have the octahedral complex species $\left[\mathrm{Al}(\mathrm{OH})_{4}\left(\mathrm{H}_{2} \mathrm{O}ight)_{2}ight]^{-}$in aqueous solution.
(3) $\mathrm{Al}(\mathrm{OH})_{3}+\mathrm{NaOH}(\mathrm{aq}) \longrightarrow\left[\mathrm{Al}(\mathrm{OH})_{4}\left(\mathrm{H}_{2} \mathrm{O}ight)_{2}ight]^{-}(\mathrm{aq})+\mathrm{NaOH}^{+}(\mathrm{aq})$ ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

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