The dissociation constant of acetic is x   ×   10 – 5   . When 25   mL   of   0 . 2   M   CH 3 COONa solution is mixed with 25   mL   of   0 . 02   M   CH 3 COOH solution, the pH of the resultant solution is found to be…

Question

The dissociation constant of acetic is x &#160; &#215; &#160; 10 &#8211; 5 &#160; . When 25 &#160; mL &#160; of &#160; 0 . 2 &#160; M &#160; CH 3 COONa solution is mixed with 25 &#160; mL &#160; of &#160; 0 . 02 &#160; M &#160; CH 3 COOH solution, the pH of the resultant solution is found to be equal to 5 . The value of x is _______.

Aicharya · Accepted Answer

The Henderson equation for the given acidic buffer can be written as

$pH = pKa + \log \frac{[salt]}{[weak acid]}$

$5 = pKa + \log \frac{25 \times 0.2}{25 \times 0.02} \Rightarrow pKa = 4 \Rightarrow Ka = 10^{- 4} = 10 \times 10^{- 5}$

Hence, the value of $x$ is $10$ .

The dissociation constant of acetic is x   ×   10 – 5   . When 25   mL  …

Solution

The dissociation constant of acetic is x &#160; &#215; &#160; 10 &#8211; 5 &#160; . When 25 &#160; mL &#160;…

Solution

The dissociation constant of acetic is x × 10 – 5 . When 25 mL …