The dissociation constant of a weak monobasic acid is $3.2 \times 10^{-4}$. Calculate the degree of…
The dissociation constant of a weak monobasic acid is $3.2 \times 10^{-4}$. Calculate the degree of dissociation in its 0.04 M solution.
- 0.0128
- 0.0151
- 0.078
- 0.089
Solution
$\mathrm{K}_{\mathrm{a}}=3.2 \times 10^{-4} ; \mathrm{c}=0.04 \mathrm{M}$
For a monobasic acid,
$\alpha=\sqrt{\frac{K_a}{c}}=\sqrt{\frac{3.2 \times 10^{-4}}{0.04}}=\sqrt{8 \times 10^{-3}}=0.089$
Asked in: MHT CET 2024 (15 May Shift 1)
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