The displacement of a particle of mass 2 g executing simple harmonic motion is $x=8 \cos \left(50 t+\frac{\pi}{12}\right) m$, where $t$ is time in second. The maximum kinetic energy of the particle is

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Aicharya · Accepted Answer

$\mathrm{m}=2 \mathrm{~g}, \mathrm{x}=8 \cos \left(50 \mathrm{t}+\frac{\pi}{12}ight) \mathrm{m}$ $\begin{aligned} & \mathrm{V}_{\max }=\mathrm{A} \omega=8 	imes 50=400 \mathrm{~m} / \mathrm{s} \ & 	herefore \quad(\mathrm{K} \cdot \mathrm{E})_{\max }=\frac{1}{2} \mathrm{mv}_{\max }^2=\frac{1}{2} 	imes 2 	imes 10^{-3} 	imes 400 	imes 400 \ & =160 \mathrm{~J}\end{aligned}$

The displacement of a particle of mass 2 g executing simple harmonic motion is $x=8 \cos \left(50…

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