The displacement of a particle in an oscillatory motion at a time ' $t$ ' is given by $\mathrm{x}=8 \sin…

The displacement of a particle in an oscillatory motion at a time ' $t$ ' is given by $\mathrm{x}=8 \sin \frac{\pi \mathrm{t}}{4} \mathrm{~cm}$, then its displacement in the time interval $\mathrm{t}=0 \mathrm{~s}$ to $\mathrm{t}=2 \mathrm{~s}$ is
  1. $4 \mathrm{~cm}$
  2. $2 \mathrm{~cm}$
  3. $12 \mathrm{~cm}$
  4. $8 \mathrm{~cm}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 2)

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