The displacement ' $\mathrm{S}$ ' of a moving particle at a time $t$ is given by $S=5+\frac{48}{t}+t^3$. Then its acceleration when the velocity is zero, is

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Aicharya · Accepted Answer

Given, $S=5+\frac{48}{t}+t^3$ Velocity $(V)=\frac{d S}{d t}=0-\frac{48}{t^2}+3 t^2$ $\begin{aligned} 	herefore \quad & V=\frac{-48}{t^2}+3 t^2 ...(i)\ & 	ext { But } V=0 ...[Given]\ & \Rightarrow \frac{-48}{t^2}+3 t^2=0 \ & \Rightarrow t=2 \end{aligned}$ Now, $\mathrm{A}=\frac{\mathrm{dV}}{\mathrm{dt}}$ $\begin{aligned} & =\frac{d}{d t}\left(\frac{-48}{t^2}+3 t^2ight) \ & =\frac{96}{t^3}+6 t \end{aligned}$ Acceleration at $\mathrm{t}=2$ is $\frac{96}{8}+12=24$

The displacement ' $\mathrm{S}$ ' of a moving particle at a time $t$ is given by $S=5+\frac{48}{t}+t^3$.…

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