The displacement due to a wave moving in the positive $x$-direction is given by $y = \frac{1}{(1 + x^2)}$ at time $t = 0$ and by $y = \frac{1}{[1 + (x - 1)^2]}$ at $t = 2 ext{ s}$, where $x$ and $y$ are in metre. The velocity of the wave (in $ ext{ms}^{-1}$) is

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The displacement due to a wave moving in the positive $x$-direction is given by $y = \frac{1}{(1 + x^2)}$ at time $t = 0$ and by $y = \frac{1}{[1 + (x - 1)^2]}$ at $t = 2	ext{ s}$, where $x$ and $y$ are in metre. The velocity of the wave (in $	ext{ms}^{-1}$) is

Aicharya · Accepted Answer

In a wave equation, $x$ and $t$ must be related in the form $(x \pm vt)$. We rewrite the given equations $y = \frac{1}{1 + (x - vt)^2}$ For $t = 0$, $y = \frac{1}{(1 + x^2)}$ and

The displacement due to a wave moving in the positive $x$-direction is given by $y = \frac{1}{(1 + x^2)}$ at…

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